Du coup voilà la suite : A = ( x² + 2x + 1 ) - ( 5x + 3 )² A = ( )² - ( 5x + 3 )² A = [ ( ) - ( ) ][ ( )
Mathématiques
kokonrd14
Question
Du coup voilà la suite :
A = ( x² + 2x + 1 ) - ( 5x + 3 )²
A = ( )² - ( 5x + 3 )²
A = [ ( ) - ( ) ][ ( ) + ( )
A = ( ) ( )
A = ( ) ( )
B = ( x² + 4x + 4 ) - ( x + 2 ) ( 2 x 5 )
B = ( )² - ( x + 2 ) ( 2 x 5 )
B = ( ) ( ) - ( x + 2 ) ( 2 x 5 )
B = ( ) [ ( ) - ( ) ]
B = ( ) ( )
B = ( ) ( )
A = ( x² + 2x + 1 ) - ( 5x + 3 )²
A = ( )² - ( 5x + 3 )²
A = [ ( ) - ( ) ][ ( ) + ( )
A = ( ) ( )
A = ( ) ( )
B = ( x² + 4x + 4 ) - ( x + 2 ) ( 2 x 5 )
B = ( )² - ( x + 2 ) ( 2 x 5 )
B = ( ) ( ) - ( x + 2 ) ( 2 x 5 )
B = ( ) [ ( ) - ( ) ]
B = ( ) ( )
B = ( ) ( )
1 Réponse
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1. Réponse Alexis94e
Salut
[tex]( x^{2} + 2x + 1 ) - ( 5x + 3 )^{2}[/tex]
[tex](x+1)^{2} -(5x+3)^{2}[/tex]
[tex](x+1-5x-3)(x+1+5x+3)[/tex]
[tex](-4x-2)(x+1+5x+3)[/tex]
[tex](-4x-2)(6x+4)[/tex]
[tex](-2(2x+1))*2(3x+2)[/tex]
[tex]-2*2(2x+1)(3x+2)[/tex]
[tex]-4(2x+1)(3x+2)[/tex]
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[tex]( x^{2} + 4x + 4 ) - ( x + 2 ) ( 2 * 5 )[/tex]
[tex]( x+2)^{2} - (2*5 ) ( x + 2 )[/tex]
[tex]( x+2)^{2} - 10 ( x + 2 )[/tex]
[tex](x+2)(x+2-10)[/tex]
[tex](x+2)(x-8)[/tex]